40W Fluorescent Lamp Inverter

 This 40W fluorescent lamp inverter allows you to run 40W fluorescent tubes from any 12V source capable of delivering 3A.

Part
Total Qty.
Description
Substitutions
R11180 Ohm 1W Resistor
R2147 Ohm 1/4W Resistor
R312.2 Ohm 1W Resistor (only needed once)
C1, C22100uF 16V Electrolytic Capacitor
C31100nF Ceramic Disc Capacitor
Q11TIP 3055 or 2N3055 or equivalent
L11See "Notes"
T11See "Notes"
MISC1Wire, Case, Board, Heatsink For Q1, heatshrink, AM antenna rod for coil
  • Wind L1/T1. You will need an AM antenna rod that is about 60mm (2.5 inches) long to wind T1/L1 on. T1/L1 are wound on the same core. Shrink a layer of heatshrink over the core to insulate it. Leave 50mm of wire at each end of the coils.
  • Primary: Wind 60 turns of 1mm diameter enamelled copper wire on the first layer and put a layer of heatshrink over it.
  • Feedback: Wind 13 turns of 0.4mm enamelled copper wire on the core and then heatshrink over that.
  • Secondary: This coil has 450 turns of 0.4mm enamelled copper wire in three layers. Wind one layer and then heatshrink over it. Do the same for the next two.

  • Calibrate/test the circuit. To calibrate/set up the circuit connect the 2.2 Ohm 1W resistor (R3) in series with the positive supply. Connect a 40W fluorescent tube to the high voltage ends of the transformer. Momentarily connect power. If the tube doesn't light immediately reverse the connections of L1. If the tube still doesn't work, check all connections. When you get the tube to light remove the 2.2 ohm resistor and the circuit is ready for use. You will not need R3 again.
  • This circuit is designed for 220V lamps. It will work with 120V units just fine, but will shorten the life of the tube.

0 comments

Post a Comment